No, a 40t is bigger. 40t vs 20t refers to the number of teeth(that engages with the chain) that each wheel has at its circumference. The tooth size is fixed for all bikes that use the same chain spacing, so a 40t chainwheel will have double the circumference of a 20t wheel.
-40t
When the bus starts, the car is already 60 miles ahead (40 mph x 1.5 hours = 60 miles). If t = time in hours, the equation looks like this:Bus 60t = Car 40t + 60.Subtract 40t from each side20t = 60Divide both sides by 20t = 3 hours
92
10t
13t front 40t rear
14t on front. 40t on back
That factors to 4t(2t + 1)(5t - 6)
1.6 ton The answer would be 40T, 1.6T is the WLL or SWL of an 8T nominal breaking strength rope.
Make shure its not teritium that's not healthy its a metal they banned in the early 60s cause it gave watchmakers cancer Search t-25 Swiss made
That's the formula for the height of an object that was tossed upward at a speed of 40 meters per second, after ' t ' seconds . This object has to be something like a canonball, or a baseball pitched by a professional etc. The initial vertical speed of 40 meters per second is almost 90 miles per hour upward !
distance = rate x timed=rt40 miles = 45 mph x time (in hours)40 = 45tSolve for t.45t = 40t = 40/45t = 8/9 hourst = (8/9) x 60 minutest = 480 / 9 minutes53.3333... minutesor0.8888... hours
To analyze the given electrical circuit, we'll use Kirchhoff's voltage law (KVL) and the relationship between voltage, current, resistance, and inductance. Kirchhoff's voltage law states that the sum of the voltage drops across the components in a closed loop is equal to the electromotive force (EMF) in that loop. Let's break down the given circuit: Electromotive Force (EMF): The EMF is given by E(t) = 100 sin(40t) V, where t represents time in seconds. Resistor: The resistor has a resistance of 10 Ω. Inductor: The inductor has an inductance of 0.5 H. Current: The current flowing through the circuit is denoted as i(t) and is initially 0 A. To find the current i(t) in the circuit, we'll apply KVL. The sum of the voltage drops across the resistor and the inductor should be equal to the EMF. Voltage drop across the resistor: V_R = i(t) * R = 10i(t) Ω Voltage drop across the inductor: V_L = L * di(t)/dt = 0.5(di(t)/dt) H Applying KVL: E(t) = V_R + V_L 100 sin(40t) = 10i(t) + 0.5(di(t)/dt) To solve this second-order linear differential equation, we need to differentiate the equation with respect to time (t): d/dt (100 sin(40t)) = d/dt (10i(t) + 0.5(di(t)/dt)) 4000 cos(40t) = 10(di(t)/dt) + 0.5(d^2i(t)/dt^2) Now we have a second-order differential equation in terms of i(t). Rearranging the terms: 0.5(d^2i(t)/dt^2) + 10(di(t)/dt) - 4000 cos(40t) = 0 To solve this differential equation, we need to find the particular solution for i(t) that satisfies the initial condition i(0) = 0. The general solution will involve complementary and particular solutions. Unfortunately, the given differential equation is nonlinear, and there is no simple analytical solution. To obtain the complete details of the current waveform, we'll need to solve this differential equation numerically using techniques like numerical integration or simulation software such as SPICE