the east /west distances are the same but the north south are different. so subtract the north from the south distances and you end up with 60 meters south.
fu
What is the displacement of a car traveling 10 km north 5km east 15 km south and 5 km north?
find the resultant of the following displacement a=20km 30south of east
What is the displacement of a car traveling 10 km north 5km east 15 km south and 5 km north?
46 squared + 23 squared = the resultant displacement squared. Pythagoras' theorem.
1 mile East
The displacement of the car is 5 km to the east.
Mary's walk resulted in a displacement of 500 meters east.
Going clockwise, the 16 directions are... North North North East North East East North East East East South East South East South South East South South South West South West West South West West West North West North West North North West ...and back to North again.
The cyclist ends up 1 mile east of the starting point (unless the cycling takes place near the north or south pole!). So the displacement is 1 mile in an easterly direction.
To calculate displacement, we determine the net change in position from the starting point. Starting at the origin, you walk 100 m north, then 20 m east, 30 m south, 50 m west, and finally 70 m south. The net movement in the north-south direction is 100 m north - 30 m south - 70 m south = 0 m, and in the east-west direction, it’s 20 m east - 50 m west = -30 m (or 30 m west). Therefore, the displacement is 30 m west.
Your displacement is 150m south. Displacement is the shortest distance and direction from the starting point to the final point, so you need to consider the overall movement, not just the sum of distances in each direction.