the east /west distances are the same but the north south are different. so subtract the north from the south distances and you end up with 60 meters south.
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What is the displacement of a car traveling 10 km north 5km east 15 km south and 5 km north?
find the resultant of the following displacement a=20km 30south of east
What is the displacement of a car traveling 10 km north 5km east 15 km south and 5 km north?
46 squared + 23 squared = the resultant displacement squared. Pythagoras' theorem.
The total displacement of the dog can be calculated using the Pythagorean theorem. After running W meters north and then W meters east, the dog's path forms a right triangle where both legs are W meters. The total displacement is the hypotenuse, which is √(W² + W²) = √(2W²) = W√2. Thus, the total displacement of the dog is W√2 meters in a northeast direction.
1 mile East
The displacement of the car is 5 km to the east.
Mary's walk resulted in a displacement of 500 meters east.
Going clockwise, the 16 directions are... North North North East North East East North East East East South East South East South South East South South South West South West West South West West West North West North West North North West ...and back to North again.
The cyclist ends up 1 mile east of the starting point (unless the cycling takes place near the north or south pole!). So the displacement is 1 mile in an easterly direction.
To calculate displacement, we determine the net change in position from the starting point. Starting at the origin, you walk 100 m north, then 20 m east, 30 m south, 50 m west, and finally 70 m south. The net movement in the north-south direction is 100 m north - 30 m south - 70 m south = 0 m, and in the east-west direction, it’s 20 m east - 50 m west = -30 m (or 30 m west). Therefore, the displacement is 30 m west.