Assume the ball's horizontal speed remains constant, since the only significant force is gravity which acts in the vertical direction. We can calculate the time of flight: time = distance / speed = 19.6m / 28ms-1 = 0.7s Consider now the vertical direction: we know that the ball took 0.7s to fall to the ground, and also that its initial vertical speed was zero. Its acceleration was g = 9.81ms-2. It is thus possible to deduce the vertical distance that it fell. s = ut + at2/2 ... but u = 0 = at2/2 = 9.81 x 0.72 / 2 = 2.40m to 3 significant figures.
As soon as it leaves the muzzle of the rifle. To hit a target at any distance, the line of sight of the barrel will be tilted so that it is ABOVE horizontal- and gravity will cause the bullet to curve back to earth- or your target.
The answer depends on the direction (upward, horizontal, or downward) in which the ball leaves his foot.
Plot distance vertical axis and time on horizontal and draw a graph with the first train leaving at zero time plot distance travelled in 4 hours I.E. 300miles draw a line. For second train start from 2 hours on time line and plot distance travelled in 4 hours I.E. 500 and draw line where they intercept draw a line to distance scale horizontally answer 375miles from the station.
No, this statement is not true. When a rifle is fired horizontally, the bullet immediately begins to drop due to gravity as soon as it leaves the barrel. The rate of drop will depend on the muzzle velocity of the bullet and the distance it has traveled.
The bullet fired horizontally will hit the ground first, given that it has an initial horizontal velocity that keeps it moving forward from the moment it leaves the gun. On the other hand, the bullet dropped from the end of the barrel only has the force of gravity acting on it, causing it to fall vertically, which is slower than the horizontal motion of the fired bullet.
Making the improbable assumption that the jumper experiences no air resistance, he will jump 3.97 metres, and reach a height of 0.72 metres.
To find the horizontal distance traveled by the shot, you can use the horizontal component of the initial velocity. The horizontal velocity can be calculated as v_horizontal = v_initial * cos(theta), where v_initial is the initial speed (15.5 m/s) and theta is the angle (34 degrees). After calculating the horizontal velocity, you can use it in the formula for horizontal distance: distance = horizontal velocity * time, where time can be calculated using the vertical component of the initial velocity to determine the time it takes for the shot to reach the ground.
just have oak leaves and sticks laid out horizontally sticks on the bottom and oak leaves above
Horizontal scrub
There necks are really long so they can reach the leaves at a high distance
The leaves of eucalyptus trees, or gum trees, grow hanging down, rather than horizontally. This is a special adaptation which minimises evaporation and hence water loss (transpiration), as the leaves are not as exposed to sunlight. The leaves usually have equal numbers of stoma on each side, unlike trees which hold their leaves horizontally - they tend to have all or most of their stoma on the lower side. The leaves also tend to have a thick, waxy coating which also minimises water loss.
A rhizome is an underground stem that can produce new leaves and roots. It grows horizontally underground and can send out shoots and roots at various points. Examples of plants with rhizomes include ginger, bamboo, and iris.