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Assume the ball's horizontal speed remains constant, since the only significant force is gravity which acts in the vertical direction. We can calculate the time of flight: time = distance / speed = 19.6m / 28ms-1 = 0.7s Consider now the vertical direction: we know that the ball took 0.7s to fall to the ground, and also that its initial vertical speed was zero. Its acceleration was g = 9.81ms-2. It is thus possible to deduce the vertical distance that it fell. s = ut + at2/2 ... but u = 0 = at2/2 = 9.81 x 0.72 / 2 = 2.40m to 3 significant figures.
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A boy starts at rest and slides down a frictionless slide The bottom of the track is a height h above the ground The boy then leaves the track horizontally striking the ground a distance d Using ener?
As the boy slides down the frictionless slide, he converts potential energy (PE = mgh) at the top into kinetic energy (KE = 0.5mv²) at the bottom. Upon leaving the slide horizontally, he retains this kinetic energy, which allows him to travel a horizontal distance ( d ) before hitting the ground. The time ( t ) it takes to fall the height ( h ) can be calculated using the equation ( t = \sqrt{(2h/g)} ), where ( g ) is the acceleration due to gravity. The horizontal distance ( d ) is then given by ( d = v_x \cdot t ), where ( v_x ) is the horizontal velocity at the bottom of the slide.
A bullet fired horizontally from a rifle begins to fall?
As soon as it leaves the muzzle of the rifle. To hit a target at any distance, the line of sight of the barrel will be tilted so that it is ABOVE horizontal- and gravity will cause the bullet to curve back to earth- or your target.
If the ball leaves his foot from a height of 4 ft write an equation for the vertical height s (in ft) of the ball t seconds after being kicked?
The answer depends on the direction (upward, horizontal, or downward) in which the ball leaves his foot.
A train leaves danville junction and travels north at the speed of 75mph tow hours later a second train leaves on a parallel track and travels north at 125 mph how far from the station will they meet?
Plot distance vertical axis and time on horizontal and draw a graph with the first train leaving at zero time plot distance travelled in 4 hours I.E. 300miles draw a line. For second train start from 2 hours on time line and plot distance travelled in 4 hours I.E. 500 and draw line where they intercept draw a line to distance scale horizontally answer 375miles from the station.
When a rifle is fired horizontally the bullet leaves the barrel and doesnt drop at all for the first 35 meters of flight Is this true?
No, this statement is not true. When a rifle is fired horizontally, the bullet immediately begins to drop due to gravity as soon as it leaves the barrel. The rate of drop will depend on the muzzle velocity of the bullet and the distance it has traveled.
A long jumper leaves the ground at an angle 20 to horizontal and at speed of 11ms.how far does he jump and what the maximum height reached?
Making the improbable assumption that the jumper experiences no air resistance, he will jump 3.97 metres, and reach a height of 0.72 metres.
A bullet is fired horizontally out of a gun at the same time another is dropped from the end of the barrelthe one to hit the ground first is?
The bullet fired horizontally will hit the ground first, given that it has an initial horizontal velocity that keeps it moving forward from the moment it leaves the gun. On the other hand, the bullet dropped from the end of the barrel only has the force of gravity acting on it, causing it to fall vertically, which is slower than the horizontal motion of the fired bullet.
A shotputter throws the shot with an initial speed of 15.5 ms at a 34.0 angle to the horizontal calculate the horizontal distance traveled by the shot if it leaves the athletes hand at a height of 2?
-- The shot leaves his hand at 15.5 m/s directed 34 degrees above the horizon.The horizontal component of its velocity is 15.5 cos(34) = about 12.85 m/s .The vertical component of its velocity is 15.5 sin(34) = about 8.667 m/s .-- The shot will continue to rise until its vertical velocity is zero. Since its verticalacceleration is -9.807 m/s2 (g), it rises for 8.667/9.807 = about 0.884 second .-- Its average speed during that time is (0.5 x 8.667) = about 4.333 m/s , and itrises (0.884 x 4.333) = about 3.983 metersabove its release height, before itstarts falling. It then has 5.983 meters to fall before it hits the ground.-- The time needed to fall 5.983 meters from the peak of its arc isT = sqrt( 2h/g) = about 1.105 second. Added to the 0.884 second that it spent on the way up, that's a total of(0.884 + 1.105) = about 1.989 seconds that it spends in the air after beingreleased.-- Its horizontal progress in that time is (12.85) x (1.989) = about 25.55 meters .
How do you make grass traps on survival craft?
just have oak leaves and sticks laid out horizontally sticks on the bottom and oak leaves above
Large Tasmanian shrub with dense leaves and foliage?
Horizontal scrub
How do giraffes get leaves from a high distance?
There necks are really long so they can reach the leaves at a high distance
How do leaves grow on a eucalyptus tree?
The leaves of eucalyptus trees, or gum trees, grow hanging down, rather than horizontally. This is a special adaptation which minimises evaporation and hence water loss (transpiration), as the leaves are not as exposed to sunlight. The leaves usually have equal numbers of stoma on each side, unlike trees which hold their leaves horizontally - they tend to have all or most of their stoma on the lower side. The leaves also tend to have a thick, waxy coating which also minimises water loss.
