Q: A rectangular city park has a jogging loop that goes along a length width and diagonal of the park To the nearest yard find the length of the jogging loop if the length of the park is 125 yards?

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Diagonal = sqrt(36 + 25) ie sqrt 61 which is 7.8 inchesto the nearest tenth.

If the sides of a rectangle (not rectangular) are X and Y units, then the corner to corner length - the diagonal - is sqrt(X2 + Y2)

Using Pythagoras' theorem the length of the diagonal is 15 units

The length of the diagonal (not diognal), is sqrt(Length^2 + Breadth^2 + Height^2).

Use Pythagoras' theorem to find the length of the diagonal of a rectangle.

13 ft

100 Feet... pathway is bisecting the rectangle into 2 right-angled triangles. Length of the hypotenuse is the length of pathway

(202 + 152)0.5 = 25"

42 cm

68m

Doesn't seem likely, does it? A diagonal 50 times the length of the sides? Diagonal = sqrt(252 + 252), ie sqrt 1250(!) which is 35.36 to the nearest hundredth.

The diagonal is SQUAREROOT(1022 + 2962) = 313.08ft Angle = tan-1(102/296) = 19.01 degrees