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This question could be answered if only it had also given either the width or the diagonal of the park.

Knowing only the length of the park, the jogging loop could still be anything at all.

Maybe there's some rule that relates the width of a rectangular city park to its length. We don't know it.

Q: A rectangular city park has a jogging loop that goes along a length width and diagonal of the park To the nearest yard find the length of the jogging loop if the length of the park is 125 yards?

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Diagonal = sqrt(36 + 25) ie sqrt 61 which is 7.8 inchesto the nearest tenth.

If the sides of a rectangle (not rectangular) are X and Y units, then the corner to corner length - the diagonal - is sqrt(X2 + Y2)

Using Pythagoras' theorem the length of the diagonal is 15 units

The length of the diagonal (not diognal), is sqrt(Length^2 + Breadth^2 + Height^2).

Use Pythagoras' theorem to find the length of the diagonal of a rectangle.

13 ft

100 Feet... pathway is bisecting the rectangle into 2 right-angled triangles. Length of the hypotenuse is the length of pathway

(202 + 152)0.5 = 25"

42 cm

68m

Doesn't seem likely, does it? A diagonal 50 times the length of the sides? Diagonal = sqrt(252 + 252), ie sqrt 1250(!) which is 35.36 to the nearest hundredth.

The diagonal is SQUAREROOT(1022 + 2962) = 313.08ft Angle = tan-1(102/296) = 19.01 degrees