If the ball is thrown at the same angel and are smiler in shape they will land at the same time the wight of the object is not what will slow it down its shape and how it resist air passing around/throw the object is what will slow it down ...
381 metres
When an object is dropped, it falls towards the ground due to the force of gravity acting on it. The object accelerates as it falls until it reaches the ground or another surface, where it comes to a stop.
44 meters tall
a. 144 feet b. 96 ft/sec.
both reaches the ground at the same time because in the moon there occurs free fall.
6 feet
The speed of the ball when it reaches the ground can be calculated using the kinematic equation: v = u + gt, where v is the final velocity (speed), u is the initial velocity (0 m/s as it's dropped), g is acceleration due to gravity (9.8 m/s^2), and t is the time taken (5.5 s in this case). Plugging in the values, v = 0 + 9.8 * 5.5 = 53.9 m/s. So, the speed of the ball when it reaches the ground would be approximately 53.9 m/s.
It could if you slammed the bouncy ball on the ground hard enough, or if you dropped it from a 30 story building. probably not
When an object is dropped off a building, the primary forces acting on it are gravity, which pulls the object downward towards the Earth, and air resistance, which acts in the opposite direction of the object's motion and increases as the object falls faster. These forces cause the object to accelerate towards the ground until it reaches a terminal velocity where the force of air resistance equals the force of gravity.
The Turning Torso, the third tallest residental building in Europe, reaches 190.4 meters above ground.
The building is h=.5 gt^2 meters tall; that is = .5x9.8 x25 =122.5 meters.
The speed of the ball when it reaches the ground can be calculated using the formula: speed = acceleration due to gravity x time taken. Given that the acceleration due to gravity is approximately 9.81 m/s^2, multiplying it by the time taken (4.5 seconds) gives a speed of approximately 44.145 m/s.