The height of the building is 57.3 meters.
30.990 metres/sec
because the blallalalalalalalalal
The height of the ball when it rebounds is 5 meters, as given in the question.
H = 1/2 G T2 = (1/2) (9.8) (4.15)2 = (4.9) (17.2225) = 84.4 meters (rounded)
The incoming angle is the angle at which something comes at some other object. For example if you hit a ball on a pool table against the side, the incoming angle is the the angle at which the ball comes at the table.
A men's water polo ball has a diameter of .22 meters, while a women's ball is .21 meters wide.
At a 5° angle down, the ball will need Vi = 1.433 m/s to hit a target .6 m from the bottom of the table. So, h = Vi²/(2g) = .105 m above the top of the table.
92 or 91.5 meters would be the maximum height.
The maximum height attained by the ball can be calculated using the kinematic equation for projectile motion. The formula to calculate the maximum height is (v^2 * sin^2(angle))/(2g), where v is the initial velocity, angle is the launch angle, and g is the acceleration due to gravity. Substituting the values, the maximum height is approximately 15 meters.
the angle that the ball is going and the force that is applied to the ball by the bat
the angle at which you hit the ball depends on maths