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Jim Roxburgh was born January 17, 1858, in San Francisco, CA, USA.

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When and where did baseball player Jim Roxburgh die?

Jim Roxburgh died February 21, 1934, in San Francisco, CA, USA.


When was Jim Roxburgh born?

Jim Roxburgh was born on 1858-01-17.


What are baseball player Jim Roxburgh's physical stats?

Jim Roxburgh is 5 feet 10 inches tall. He weighs 170 pounds. He bats right and throws right.


When and where did baseball player Jim Roxburgh play?

Jim Roxburgh debuted on May 30, 1884, playing for the Baltimore Orioles at Oriole Park; he played his final game on June 9, 1887, playing for the Philadelphia Athletics at Jefferson Street Grounds.


When did Jim Roxburgh die?

Jim Roxburgh died on 1934-02-21.


What were baseball player Jim Roxburgh's total batting stats for 1887?

In 1887, Jim Roxburgh played in 2 games, all for the Philadelphia Athletics, and batting in all of them. He had 8 at bats, getting 1 hit, for a .125 batting average, with 0 runs batted in. He was walked 0 times. He struck out 0 times. He hit only singles.


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