11
Wiki User
∙ 15y agoAdd the two year values together and subtract 1, to allow for the fact that there was no year zero. So from 1 BC to 1 AD is 1 year. 1 + 1 - 1 = 1. From 10 BC to 40 AD is 49. 10 + 40 - 1 = 49.
The pattern is Add 1, then 2, then 1, then 2 again. Easy!
"Asian" is not a language. Therefore, you cannot say 1 through 10 in "Asian".
its 1 minit more than 9 past 10
The basic and most common Roman numbers are as follows:I = 1V = 5X = 10L = 50C = 100D = 500M = 1000The rules for using them are fairly simple, using specific placement of the numbers to indicate addition or subtraction to the base number. For the most part, you add the values of the letters until placement tells you to do otherwise. If you need to add three, or less, to the base number, then place the added numbers to the right of the base number. For example, the number '8' would be written VIII (5 + 3) and the number '13' would be written XIII (10 + 3). If you need to add four to the base number, then you express this by subtracting one from the base number, and placing the number to the left of the base number. For example, the number '4' is written IV (5 - 1), and the number '9' is written IX (10 - 1). For more elaborate examples, the year '2010' would be written MMX (1000 + 1000 + 10), and the year '1964' would be written MCMLXIV (1000 - 100 + 1000 + 50 + 10 - 1 + 5).
-10+11= 1
10/5 = 2 10/10 = 1 2+1=3
When you add -9 and +10, you get (+) 1.
you need to add 3/10 to 7/10 to get 10/10 or 1.
add -10... 11 + (-10) = 11-10=1 ur welcome! So that would be 2x + 11 = 1 where x = -5.
add 1 through 10 times 10 then add 10 through 90 and add the answers
1/10 = 10/100. 10/100 + 1/100 = 11/100
10
11
-1
1/10+1/10=2/10 which reduces to 1/5
if u half it you can multiply it by 10 and there is your answer but buy checking add the digets toether they should add up to 10