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Not in the same season because there aren't enough games. Under the current NFL scheduling system, every team is guaranteed to play every other team at least once every four years. In a 16-game season, a schedule breaks down as follows: * 2 games against each divisional opponent. Total of 6 games. * 4 games against every team in another division within the conference, on a three-year rotation. Total of 4 games. * 4 games against every team in another division in the opposing conference, on a four-year rotation. Total of 4 games. * 1 game against the teams in the non-rotation divisions within the same conference who finished in the same position the previous season. (In other words, if Team A finished in first place in its division last year, they would play whatever division was in rotation that year, plus the teams who placed first in the two other non-rotation divisions in the previous year.) Total of 2 games.

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15y ago
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10y ago

No. The NFL (National Football League) is make up of 2 conferences. The AFC and NFC. Each conference is also broken down into 4 divisions, for a total of 8 divisions in the NFL. Throughout a typical NFL season teams usually play other teams within their own conference. NFC teams play other NFC teams, and AFC teams play other AFC teams. Teams sometimes do play a team from another conference from time to time but it doesn't happen regularly.

The only time that NFC and AFC teams regularly play each other is during the pre-season (exibition) games which are not part of the regular season, and the Super Bowl which is (supposedly) the best NFC team against the best AFC team.

NOTE: Very often, the teams in one conference may be far superior to teams in the other conference. That is why some Super bowls are a complete blowout even though the teams playing are technically the top 2 teams.

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Q: Does each NFL team play every other team?
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