Yes.
If you have a pair of aces, that's equal to 11 points each. That's 22 points. 9 add 9 is 18, plus 20 (10 add 10) is 38 points. The player with the 9's and 10's would win the pot. In other words, two pairs beat one pair, no matter the cards involved.
Two pairs of aces (called 4 of a kind) does beat a flush.
Yes always. e.g. three sevens (777) beats a pair of kings and a pair of aces (KKAA)
yes
No, in Texas Hold'em, a 3 of a kind hand beats a 2 pairs hand.
Depends what card game it is.
Double aces is a pair, it would be beaten by a three of a kind, unless someone else has a pair of aces also, in which case the next highest card in the hand would win. For example: between the hands of A, A, 10, 6, 2 and A, A, 7, 4, 3 the 10 would win. a pair of 1,2,3,4,5,6,7,8,9,10,jack,queen, or king would beat a pair of aces.
Three aces and two eights is a full house. Three Aces and two nines would win. As would three aces and two kickers 10 or higher.
No not in cards
3 of a kind Aces can not beat a full house. In this particular case it is most likely that there was a pair and an ace already on the board, making the 3 aces and the pair on the board a higher full house then the other full house.
The pair of queens beat the pair of tens, the nine and the ace are irrelevant. Queens are higher ranked than tens.
Depends on the value of the Ace and 5, Aces are used as the highest or lowest values in different games. if an ace has any positive value however, 2 aces and 2 fives would beat 1 ace and 2 fives.
You be amazing and beat the crap out of them