Answer: It depends upon your definition of "work". Assuming the lifter put the barbell back exactly where and how it was at first, then there was no work done in the physics context. If you mean manual labor, then yes, some work was done.
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While just holding the weight on his shoulder, the weight lifter does no work! For work to be done, the mass must be moved through a distance … No Movement, No Work! (but don't tell that to a weight lifter …)
To calculate the work done, we need to know the distance over which the weight lifter held the weight. If we assume the weight lifter held the weight steady at shoulder height (about 1.5 meters), the work done would be Weight x Height = 120 kg x 1.5 m = 180 Joules.
If the dumbbell does not move, then the work done by the weight lifter is zero. This is because work is defined as force applied over a distance in the direction of the force, and if there is no movement, no work is done.
Muscular energy is used when someone lifts a barbell to momentary muscular failure. This involves the contraction of muscles against resistance to lift the weight. Additionally, potential energy is converted to kinetic energy as the barbell is lifted against gravity.
The work done by the weight lifter is calculated by the formula: work = force x distance. In this case, the force is 400 newtons (200 newtons + 200 newtons) and the distance lifted is 1 meter for each weight, totaling 2 meters. Therefore, the work done is 800 joules (400 N x 2 m).
The work done by the weight lifter holding a weight of 80 kg on his shoulder for 2 minutes is zero, assuming he remains stationary. Work is calculated as force multiplied by displacement in the direction of the force, and since there is no displacement in this case, no work is done.
The work done would be zero, since the weight lifter is not moving the weight vertically. Work is defined as force applied in the direction of motion. Holding a weight in a static position does not result in any work being done.
none. work is done when a force is applied thru a distance. holding something stationary does no work.
The weight of the mass 'm' is (m g) .That's the minimum force he has to exert in order to balance the force of gravity andlift the weight vertically. If he exerts more force than (mg), the weight will accelerateup, and he'll just wind up either coasting in the middle, or else retarding it at the top.So the eventual outcome is just applying the force (mg) through the distance 'h'.The time taken for the maneuver has no effect on the work done. It's just the amount ofpotential energy gained by the bar-bell due to its increased elevation.Work = [ (force) times (distance) ] or [ (weight) times (height) ].W = m g h
Weightlifting competitions at the 2012 Summer Olympics in London were held from 28 July to 7 August 2012 and done by weight class and by Men and Womens for the 15 events Total score was the sum of the lifter's best result in each of the snatch and the clean and jerk, with three lifts allowed for each lift
The work done in lowering the weight is equal to the force of gravity (150 kg * 9.8 m/s^2) times the distance moved (2 m). This gives us the total work done. To calculate power, we divide this work by the time taken (5 seconds). This gives us the power used by the weight lifter in lowering the weight.
The work done in lifting the barbell is given by the formula: Work = force x distance = 500 N x 2.2 m = 1100 J. The potential energy of the barbell at this height is equal to the work done, so it would also be 1100 J.