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What is the maximum distance between nodes?
lamda /2
How do you calculate the work of a spiral spring?
Hi, I may be wrong and correct me if i am. Work is the force applied over a distance: F x d. So to calculate the work of a spiral spring it would be the spring coefficient (usually denoted as "k") times the distance. But you have to remember that the spring force is kxd, so you have to integrate the force over the distance, which will yield the following equation: work is equal to 1/2 the spring constant times the distance squared. W=(1/2) k d2
What is the difference between clear and effective span?
distance b/w 2 supports is clear span. then c/c dis b/w 2 supports is eff span
Ahman is trying to lift an 8-N load that is attached to a fixed 2-pulley system his hands move a distance of 1.6m while the load moves 0.8mwhat force is required?
Assuming the pulleys are frictionless, which they are pretty close to: You have a mechanical advantage of 2, hence your hands move double the distance that the load moves. So you only need half the force, 8N / 2 = 4N.
What is the relationship between acceleration and distance?
displacement (s)=initial velosity(u)*time(t) + 1/2 acceleration (a)*(t^2) from a stationary start this simplifies to s=1/2a(t^2) this arises from the fact that a is the second integral of s with respect to time eg. d/dt=s: x=st+u (velosity v=distance*time +initial velosity) (d^2)/d(t^2)= s(t^2)/2+ut+d=a as we are measuring displacement and not position, the constant of integration d drops, leaving a=s(t^2)/2+ut : s=ut+1/2a(t^2)
