hopefully
No don't worry they will reunite one day
Considering a fact that both HHH & HBK are out of action, I guess, their return as DX would be great for WWE Universe. Especially to shock Legacy. There's some payback which are to be settled with HHH & HBK when we speak about Randy. What do you guys think?????
dx dx dx dx dx dx dx dx dx dx dx dx dx dx dx dx dx d dx dx dx dx dx dx dx dx
when Shawn micheals beats Shane McMahon and triple h beats mr mr. McMahon in one night then DDDDDXXXX will reunite!!!! THEY ARE MY FAVORITE TAG TEAM!!! Steven Rega Junior SUCK IT
they are on and off. They get together when one of them needs a tag team partner or for a promo. They never left. Its just that they're too busy doing their own stuff, but they do reunite occassionally
I will reunite this man with his wife
Rumors are that they might reunite for the Warped Tour in 09.
After many years of turmoil the lovers will reunite at sunset this upcoming Valentine's Day. Why would you want to reunite with THAT family member? Everyone feared the storm sure to come when the brothers would reunite. Won't it be wonderful when they finally reunite? After pusuing solo careers, the three original members of the rock band decided to reunite for one last world tour.
Yes the will reunite! They belong together! Feb. 4th baby!
Yes he did. He built indestructible Forces to reunite Japan
5ex+2?d/dx(u+v)=du/dx+dv/dxd/dx(5ex+2)=d/dx(5ex)+d/dx(2)-The derivative of 5ex is:d/dx(cu)=c*du/dx where c is a constant.d/dx(5ex)=5*d/dx(ex)-The derivative of 2 is 0 because it is a constant.d/dx(5ex+2)=(5*d/dx(ex))+(0)d/dx(5ex+2)=5*d/dx(ex)-The derivative of ex is:d/dx(eu)=eu*d/dx(u)d/dx(ex)=ex*d/dx(x)d/dx(5ex+2)=5*(ex*d/dx(x))-The derivative of x is:d/dx(xn)=nxn-1d/dx(x)=1*x1-1d/dx(x)=1*x0d/dx(x)=1*(1)d/dx(x)=1d/dx(5ex+2)=5*(ex*1)d/dx(5ex+2)=5*(ex)d/dx(5ex+2)=5ex5ex+2?d/dx(cu)=c*du/dx where c is a constant.d/dx(5ex+2)=5*d/dx(ex+2)-The derivative of ex+2 is:d/dx(eu)=eu*d/dx(u)d/dx(ex+2)=ex+2*d/dx(x+2)d/dx(5ex+2)=5*(ex+2*d/dx(x+2))-The derivative of x+2 is:d/dx(u+v)=du/dx+dv/dxd/dx(x+2)=d/dx(x)+d/dx(2)d/dx(5ex+2)=5*[ex+2*(d/dx(x)+d/dx(2))]-The derivative of x is:d/dx(xn)=nxn-1d/dx(x)=1*x1-1d/dx(x)=1*x0d/dx(x)=1*(1)d/dx(x)=1-The derivative of 2 is 0 because it is a constant.d/dx(5ex+2)=5*[ex+2*(1+0)]d/dx(5ex+2)=5*[ex+2*(1)]d/dx(5ex+2)=5*[ex+2]d/dx(5ex+2)=5ex+2