Player (Country)
Venue
Against
Score
Year
G Kirsten (SA)
Rawalpindi
UAE
188*
1996
Sourav Ganguly(Ind)
Taunton
183
1999
V Richards (WI)
Karachi
Sri Lanka
181
1987
K Dev ( Ind )
Tunbridge Wells
Zimbabwe
175*
1983
K Wishart (Zim)
Harare
Namibia
172*
2003
G Turner (NZ)
Birmingham
171*
1975
A Hudson (SA)
Rawalpindi
161
1996
Sachin Tendulkar(Ind)
Pietermaritzburg
Namibia
152
2003
R Dravid ( Ind )
Taunton
Sri Lanka
145
1999
A de Silva (SL)
Kandy
Kenya
145
1996
Sachin Tendulkar has scored maximum runs in the whole world.
tendulkar
The Bangladeshi batsman who scored the highest number of runs at the 1999 Cricket World Cup was Minhajul Abedin - whose 140 runs in four innings eclipsed the next best, 120 runs in 5 innings, scored by Mehrab Hussain. Abedin's average was significantly better than any other player's, with a 1999 World Cup average of 70.00.
India against Bermuda they made 413
20
Dwayne Bravo
ponting
Don Bradman scored fastest 2000 runs in test cricket in just 22 innings.
When a batsman scores 100 runs in a innings, it is called a century.
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When a batsman scores 100 runs in a innings, it is called a century.
For this explanation, I will assume one batter is equal to one plate appearance and since the number of innings is not specified, I will assume a 9 inning game. These assumptions would make the answer 112.The maximum number of batters in a half inning where no runs were scored would be 6 (3 outs, 3 runners left on base), the maximum number of batters in a half inning, other than the bottom of the final inning, where 1 run was scored would be 7 (3 outs, 3 runners left on base, 1 run scored), and the maximum of batters in a half inning, other than the bottom of the final inning, where 2 runs were scored would be 8 (3 outs, 3 runners left on base, 2 runs scored).The visiting team would score 2 runs in 1 inning and no runs in 8 innings or 1 run in 2 innings and no runs in 7 innings. This would give them a total of 56 batters regardless of whether they scored 1 run in 2 innings ((7 * 6) + (2 * 7) = 56) or 2 runs in 1 inning ((8 * 6) + (1 * 8) = 56).Through the home team's first eight at bats, they would score 2 runs in 1 inning and no runs in 7 innings or 1 run in 2 innings and no runs in 6 innings. This would give them a total of 50 batters entering the bottom of the ninth regardless of whether they scored 1 run in 2 innings ((6 * 6) + (2 * 7) = 50) or 2 runs in 1 inning ((7 * 6) + (1 * 8) = 50). In the bottom of the ninth, the home team would score the run to give them the 3-2 win. The maximum number of batters would be 6 (2 outs, 3 runners left on base, 1 run scored). This would give the home team a total of 56 batters.Both teams would send 56 batters to the plate for a game total of 112.