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When did baseball player Abe Alvarez play?
Abe Alvarez debuted on July 22, 2004 and played his final game on May 21, 2006.
What are baseball player Abe Alvarez's physical stats?
Abe Alvarez is 6 feet 2 inches tall. He weighs 190 pounds. He bats left and throws left.
When was Abe Alvarez born?
Abe Alvarez was born on October 17, 1982, in Los Angeles, California, USA.
How tall is Abe Alvarez?
Abe Alvarez is 6' 2".
What is the birth name of Abe Alvarez?
Abe Alvarez's birth name is Abraham Alvarez.
When and where was baseball player Abe White born?
Abe White was born May 16, 1904, in Winder, GA, USA.
When and where was baseball player Abe Wolstenholme born?
Abe Wolstenholme was born March 4, 1861, in Philadelphia, PA, USA.
When and where was baseball player Abe Bowman born?
Abe Bowman was born January 25, 1893, in Greenup, IL, USA.
What were baseball player Abe Alvarez's batting stats for 2006?
In 2006, Abe Alvarez played in 1 games, batting in all of them. He had 1 at bats, getting 0 hits, for a .000 batting average, with 0 runs batted in. He was walked 0 times. He struck out 1 times.
When and where was baseball player Abe Kruger born?
Abe Kruger was born February 14, 1885, in Morris Run, PA, USA.
What were baseball player Abe Alvarez's total batting stats for 2006?
In 2006, Abe Alvarez played in 1 game for the Boston Red Sox. He had 1 at bat, getting 0 hits, for a .000 batting average, with 0 runs batted in. He was walked 0 times. He struck out 1 time.
What were the fielding stats for baseball player Abe Alvarez playing at pitcher for the Boston Red Sox in 2005?
Abe Alvarez played in 2 games at pitcher for the Boston Red Sox in 2005, starting in none of them. He played for a total of 7 outs, equivalent to .26 9-inning games. He made no putouts, had one assist, and committed no errors, equivalent to 0 errors per 9-inning game. He had no double plays.
