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newton's first law states: an object will remain at rest or at a constant velocity unless the forces on it become unbalanced. As the forces on the object are now balanced it falls at a constant velocity. For falling objects this is called the terminal velocity
An object that has reached its terminal velocity is going at a constant velocity. Acceleration is the rate of change of the velocity. The rate of change is zero. Therefore, the acceleration is zero.
An arrow shot vertically into the air will lose velocity and reverse direction. When it begins to descend, the fletching will quickly cause it to re-orient with the point downward. It will accelerate until it reaches its terminal velocity. Assuming an atmospheric density of 1.3 kg/m^3, and an arrow with a drag coefficient of 1.2, a weight of 0.23 N (200 grains), cross-sectional area of 23.48 mm^2, I calculate a terminal velocity of 112.6 m/s. That's about the same as the initial velocity when shot from a compound bow! One question remains, however: does the arrow have enough time during its descent to reach terminal velocity? That would depend on how high you shot it in the first place. Roughly speaking, though, the faster it was going when it left the bow, the faster it will be going when it reaches the ground.
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Which ever object has the lowest terminal velocity since it will take longer to accelerate to a higher velocity. Galileo showed that dissimilar object fall at similar rates and in the absence of air both objects would fall at an identical rate.
During free fall, the parachutist reaches a terminal velocity (a constant velocity) of somewhere between 120 and 180 miles per hour. (If you go feet first, you go faster than if you lie on your back or front). When the parachute opens (hopefully), the terminal speed is reduced to around 12 miles/hour.
You got it right the first time. STYROFOAM.
As Galileo demonstrated, acceleration is independent of mass, therefore, they would reach terminal velocity at the same time. This is, of course, ignoring air friction.
It depends on the type of bubbles. Hydrogen bubbles are often used to visualize aerodynamic flows around models. How you would work out their terminal velocity is by balancing their drag force and buoyancy force. First you would need an estimate of the bubble diameter, somewhere around .025 mm. For water, density of fluid =998 kg/m3 and fluid viscosity = 1.12*10-3 Pa*s FB=density of fluid*volume of bubble*gravity FD=3*pi*fluid viscosity*diameter*velocity of water At the terminal velocity FD=FB, you should have all the other variables, just rearrange to solve for the terminal velocity.
Panic?Terror?Exhilaration?No, "FREE-FALL". Although one or more of the first three are likely, as well.By the way; a skydiver is only in freefall for about a second after the jump. After that, the air resistance of his body begins to slow him down until he reaches "terminal velocity".
If you drop an elephant and an equal weight amount of feathers, the elephant will hit the ground first. The elephant falls faster than the feather because it never reaches a terminal velocity; it continues to accelerate as it falls accumulating more and more air resistance.
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