The total momentum of the two balls.
The sum of the momentums.
A baseball flies through an open window and collides with a vase. The momentum of the ball and vase after the collision is the same as the momentum of the ball alone before the collision.
No. The thing that is the same before and after the collision is the total momentum.
By the Law of Conservation of Momentum, the total momentum after the collision must be the same as the total momentum before the collision.
No loss in energy due to collision is for elastic collision. But there will be a loss during collision in case of in-elastic collision. So KE will remain constant before and after collision in case of elastic collision.
The same as the total momentum before the collision.
That means that total momentum doesn't change. It is the same before and after the collision.
The sum of the momentum of the two toys before the collision will be the same as the momentum of the two toys after the collision except for some losses due to heat dissipation and frictional losses.
Same as before the collision. This applies whether the collision was elastic (no loss of kinetic energy) or inelastic (some kinetic energy lost).
The total momentum before the collision is the same as the total momentum after the collision. This is known as "conservation of momentum".
You didn't supply enough information to solve this problem. Two formulae are important to solve problems with momentum: (1) the definition of momentum: momentum = mass x velocity. (2) the total momentum (sum of individual momenta) before and after the collision must be the same.
There is a Law of Conservation of Momentum, which states that total momentum is always conserved. In this case, that means that - assuming no additional bodies are involved - the total momentum before the collision will be the same as the total momentum after the collision. It doesn't even matter whether the collision is elastic or not.