The answer is six.
Load the bases with 3 singles (3)
single up the middle, runner thrown out at home 3 times in a row. (6)
The answer is six, but not in the manner listed above, which are actually 3 fielders choices. The real answer is:
2 singles to start the inning. Runners at first and second.
2 more singles with the lead runner thrown out at home. First and second, two out.
1 more single to load the bases. Bases loaded, two out.
The sixth batter hits a ball that hits one of the runners. The runner is the third out, and the batter is credited with a single.
Milwaukee vs. Toronto (31 hits) august 28th, 1992.
on April 18th, 2009 the Cleveland Indians set a major league record scoring 14 runs in one inning.[2nd inning]
13 times, a team has gotten shut out on 13 hits
me
That;s an easy one: 3 out---3 left on base--1 took a pitch and was subbed due to injury. That is not possible. The most batter that could come to the plate in an inning with out a runs scoring is 6.
I don't know what the actual answer is, but I say 6 hits without scoring a run is theoretically possible: three hits to load the bases, two fielder's choice outs of the lead runners, then two more singles to load the bases again. Then the 6th hit would be a batted ball into a baserunner. The baserunner would be the 3rd out and the batter is credited with a hit. Or the 6th hit could be, although unlikely, an infield hit where there's an attempted putout at 1st, then the batter rounds 1st in attempt to go to 2nd and is immediately tagged out before the run crosses the plate.
Ichiro
NY Rangers
John obi mikel
Andre Reed
objective scoring means that you win a sport by scoring most goals!
Spahn