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When skydiver slows down from 54 meters to 4 meters by opening his parachute If this takes 0.75 seconds what is the magnitude of the skydiver's acceleration?
the magnitude of the skydivers acceleration is zero as he is decelerating by opening his parachute!
A skydiver slows down from 54 ms to 4 ms by opening his parachute If this takes 0.75 seconds what is the magnitude of the skydivers acceleration?
66.7 m/s2
A skydiver slows down from 65 ms to 5 ms by opening the parachute If this takes 0.75 seconds what is the skydivers acceleration?
80 m/s2 up
A skydiver slows down in 54 ms to 4 ms by opening his parachute if it takes 0.75 What is is the magnitude of the skydivers acceleration?
To find the acceleration, we first calculate the change in velocity: 4 m/s - 54 m/s = -50 m/s. Next, we use the formula for acceleration: acceleration = change in velocity / time = -50 m/s / 0.75 s = -66.67 m/s^2. The magnitude of the acceleration is 66.67 m/s^2.
A skydiver slows down from 54 m s to 4 m s by opening his parachute this takes 0.75 seconds what is the skydivers acceleration?
He will decelerate (meaning an acceleration in the direction opposite of current velocity) at a rate of (54 m/s - 4 m/s)/.75 seconds = 66.67 m/s2. This is about 6.8 Gs.
How can one determine the magnitude of acceleration in a given scenario?
To determine the magnitude of acceleration in a given scenario, you can calculate it by dividing the change in velocity by the time it takes for that change to occur. This is represented by the formula: acceleration (final velocity - initial velocity) / time. The resulting value will give you the magnitude of acceleration in the scenario.
Acceleration takes place when?
Acceleration occurs when there is a change in an object's velocity, either in magnitude or direction. This change can result from an increase or decrease in speed, or a change in the object's path of motion. Acceleration is a vector quantity, meaning it has both magnitude and direction.
A skydiver slows down from 54 ms to 4 ms by opening his parachute. If this takes 0.75 seconds what is the magnitude of the skydiver's acceleration?
66.7 m/s2
What is the acceleration experienced by a car that takes 10 seconds to reach 27 meters per seconds from rest?
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
A car traveling at 8 meters per second due north speeds up to 10 meters per second in the same direction If it takes the car 5 seconds to change its velocity what is the car's acceleration?
Magnitude of acceleration = (change in speed) / (time for the change) = 2/5 Acceleration = 0.4 meters per second2 north
Change in velocity divided by the thime it takes for the change to occur?
That would be the magnitude of the average acceleration during that period of time.
A skydiver slows down from 54 ms to 5 ms by opening his parachute. If this takes .75 seconds what is the magnitude of the skydiver's acceleration?
The change in velocity is 54 m/s - 5 m/s = 49 m/s. The time is 0.75 seconds. Using the equation a = (vf - vi) / t, the acceleration is (49 m/s) / (0.75 s) = 65.33 m/s^2.
