In Major League Baseball what is the distance from first base to second?

Answer 1

Approximately 127 feet

All of the bases are 90 feet apart.

So you have a right triangle. To find the hypotenuse of a right triangle you can use the pythagorean theorem: A^2 + B^2 = C^2

90 ^2 + 90 ^2 = C ^2

8100 + 8100 = C^2

The square root of 16200 is 127.27 That measurement is from the tip (back) of home plate to the center of second. Home plate, first and third base are completely within the 90 ft per side square (diamond) that makes up the infield. The center of second base is at the intersection of the 1-2 and 2-3 baselines and therefore partially (well mostly) outside the diamond.

Answer 2

90 feet

1st to 2nd: 90 feet

2nd to 3rd: 90 feet

3rd to home: 90 feet

Home to 1st: 90 feet

2nd to home: 127 feet

Pitcher's mound to home: 60 feet 6 inches

Answer 3

63.7170 feet or about 63' 8.6" which is just shy of an inch less than half the distance between home and second. Seems counter intuitive but simple geometry.

We know distance from mound to home 60' 6", and home to first 90'. If you draw a line from first to third and home to second, it creates a isosceles triangles with sides of 63.64 and 90 feet. The distance from mound to the center point is 63.64 minus 60.5 or about 3.14 feet. Square the two sides of this new triangle, add them, and take the square root of the sum and you 63.717 or 0.077 feet, times 12 to convert to inches, or 0.92 inches. Almost the same as what you would estimate by guessing half the distance from home to third.

Answer 4

The distance varies based on the league. Baseball (NCAA and MLB) is 90 feet. Softball is between 60 and 90 feet, depending on underhand or overhand, or mens and womens.

Answer 5

127.28 feet

Answer 6

60 feet

Answer 7

90 Feet.