NK Slavonac is a Croatian football club based in a village Stari Perkovci in Slavonia.
If you mean knicker, like trousers, k-n-i-c-k-e-r
Slavonic Channel International was created in 1994.
for (n=1; n<1000; ++n) { for (sum=0, k=1; k<=n/2; ++k) if (n%k==0) sum += k; if (sum==n) printf ("%d\n", n); }
"Glory to God" in Slavonic is "Slava Bogu."
I d o n ' t k n o w ! :D
The degrees of freedom is a count of the number of variables which are free to vary. This number can be fewer than the number of variables because of constraints imposed by additional information. Suppose, for example, you have n variables and you also know their mean. Knowing the mean is effectively the same as knowing their sum. So (n-1) of the variables can take any value but, after that, the nth variable must be such that all n of them add to the know sum. Similarly, if you have n variables and are given k means (for k classes), then only n-k of the variables are free to take any value. There are k constraints imposed by the k means.
No, he does not have. He is a normal Hindu person. His accent has Russian or Slavonic.
Russian-Armenian - Slavonic - University was created in 1997.
Russian-Tajik Slavonic University was created in 1996.
k = f(n) = 7n
In Greek mythology, the Winged Goddess of Victory.
#include<iostream.h> #include<conio.h> void main() { clrscr(); int i,k,a[10],c[10],n,l; cout<<"Enter the no. of elements\t"; cin>>n; cout<<"\nEnter the sorted elments for optimal merge pattern"; for(i=0;i<n;i++) { cout<<"\t"; cin>>a[i]; } i=0;k=0; c[k]=a[i]+a[i+1]; i=2; while(i<n) { k++; if((c[k-1]+a[i])<=(a[i]+a[i+1])) { c[k]=c[k-1]+a[i]; } else { c[k]=a[i]+a[i+1]; i=i+2; while(i<n) { k++; if((c[k-1]+a[i])<=(c[k-2]+a[i])) { c[k]=c[k-1]+a[i]; } else { c[k]=c[k-2]+a[i]; }i++; } }i++; } k++; c[k]=c[k-1]+c[k-2]; cout<<"\n\nThe optimal sum are as follows......\n\n"; for(k=0;k<n-1;k++) { cout<<c[k]<<"\t"; } l=0; for(k=0;k<n-1;k++) { l=l+c[k]; } cout<<"\n\n The external path length is ......"<<l; getch(); }