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If you and 6 of your friends are running in a race how many ways can you place first through seventh?
The equation is 7! which means that there is 7X6X5X4X3X2X1 different ways of finishing. 7!=5040.
How many ways can you arrange 4 out of 8 books on a shelf?
There are 8 ways to choose the first book There are 7 ways to choose the second book - 8 x 7 = 56 ways to select two books There are 6 ways to choose the third book - 8 x 7 x 6 = 336 way to select three books There are 5 ways to choose the fourth book - 8 x 7 x 6 x 5 = 1,680 ways to select four books.
How many different ways can 7 people stand in line for movie tickets?
There are 7 people who could stand first, with 6 people who could stand second for each of those first people, with 5 people who could stand third for each of those first two people, and so on, until with 1 person left who could stand seventh for each of the first six people. This gives 7 × 6 × 5 × ... × 1 = 5040 ways.
How many ways can 2 CD's be selected from a set of 8 CD's if the first CD is not returned to the set after playing it?
8P2= 8*7= 56 ways
How many ways can 7 books be arranged vertically on a bookshelf?
If the books have to be the correct way up and spine outwards: 7! ways =7x6x5x4x3x2x1 =5040 ways. If the books can be any way in (upside down, spine inward, etc.): (7!x4^7) ways =7x4x6x4x5x4x4x4x3x4x2x4x1x4 =82,575,360 ways
What are every possible 8 digit combinations of the numbers 0 through 9?
There are 10 numbers 0,1,2,3,4,5,6,7,8,9 in all. Case 1: assuming that the numbers can repeat. The first digit can be chosen in 9 ways (exclude 0). The second in 10 ways(include 0) and so on. Total number of combinations is 9 x 10^7 (that is 9 times 10 to the power 7) ways. Case 2: assuming that the numbers cannot repeat. The first digit in 9 ways, the second digit in 9 ways, the 3rd in 8 ways, the 4th in 7 ways and so on. Total number of permuations is 9 x 9 x 8 x 7 x 6 x 5 x 4 x 3 =1632960 ways
How many ways can 7 people be arranged?
Imagine lining 7 people in a row. You have 7 people to choose from for the first person and 6 people to choose from for the second person and so on and so on , so answer=7x6x5x4x3x2x1
How many ways can 7411111 be arranged?
The answer is 7!/5! = 42 ways.
How many Ways can you make 7 using 3 dices?
There are 15 ways to make 7 using 3 dice.
What are other ways to express the fourth power of 7?
492 or 3434/3 or (1/7)-4 are some ways.
How many ways can 4 people be chosen and arranged in a straight line If there are 7 people from whom to choose?
There are 840 ways for selecting 4 people from 7 and arranging them in a straight line. There are 7 choices for the first person. For each of those 7 choices, there are 6 for the second. For each of those 7 x 6 there are 5 for the third. And for each of those 7 x 6 x 5 there are 4 choices for the fourth Making a grand total of 7 x 6 x 5 x 4 = 840 ways.
How many ways can 7 objects be arranged in a row?
Factorial 7 (7!) ie 7 x 6 x 5 x 4 x 3 x 2 = 5040 different ways. Look at it this way: The first place can be taken by any of the 7 objects, which leaves any of 6 objects available for second place, which leaves any of 5 objects...
