yes
Acceleration is the change of speed upward. Velocity is any speed, in a fixed direction. So the diference, is that in speed; the direction can change, but the speed remain constant. Only if it moves faster or slower dose the speed change. So in velocity, if the speed, or the direction change, then the velocity changes.
The velocity changes from [ V upward ] to [ V downward ].The total change in velocity is [ 2V ].Acceleration = (change in velocity) divided by (time for the change) = 2V/6But the acceleration is just the acceleration of gravity = 9.8 meters / sec2 .9.8 = 2V / 62V = 58.8V = 29.4 meters per second upward
Sure. Anything you toss with your hand has constant acceleration after you toss it ... the acceleration of gravity, directed downward. If you toss it upward, it starts out with upward velocity, which reverses and eventually becomes downward velocity.
Acceleration is defined by physics as the rate of change of velocity over time. a = dv/dt As time changes, any change in velocity results in a change in acceleration. That change can be positive or negative. If you want to know why, its because acceleration and velocity are vectors. A vector has a magnitude and a direction. The magnitude is the value, and the direction refers to the direction the object is traveling. An example when acceleration doesn't point in the same direction as velocity is when you throw a ball into the air. You throw it up, so the initial velocity is in the upward direction. However the acceleration due to gravity is downward. It will slowly decrease the upward velocity of the ball until it is zero. At that point the ball will start to fall downard and increase in velocity until it hits the ground.
Just before it reaches the highest point, the vertical component of velocity is upward.Just after it passes the highest point, the vertical component of velocity is downward.There's no way you can change from an upward velocity to a downward velocity smoothlywithout velocity being zero at some instant. A.True.
It will take 9.8m/s squared. that is my guesstimate.
its upward at some specified angle
Answer:Yes, but only instantaneously.Consider a thrown ball moving directly upward. At the highest point of its trajectory, the instanataneous velocity (the velocity at that precise instant) is zero even while the acceleration due to gravity remains non zero.
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
The maximum height of a thrown ball is dependent on the upward portion of the initial velocity. Air friction will slow it somewhat but gravity will cause it to lose most of its upward velocity. The velocity will decrease by 9.8 m/sec for each second of its upward motion, until it reaches zero. At that point, the ball is pulled back toward Earth.
A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
If the object is moving upwards with a constant velocity, there is only one arrow in the diagram, and it points straight down, due to gravity. If it has a force pulling upward on it, there are two arrows, one up, due to the force, and one down, again, due to gravity.