Math I know; Basketball I'm a little weaker on.
Assuming that each of the five positions is distinct there are 8! / 3! or 6720 possible combinations.
Assuming that all of the five positions are the same (I know this isn't true; I'm just putting it up for comparison) there are 8 choose 5 ( 8!/(3!*5!)) or 56 possible combinations.
If some of the positions are the same but others aren't, then the answer is somewhere in between.
5
The first position can be filled by eight, the second by seven, and so on. So the number of possibilities are: 8!/3! = 8*7*6*5*4 = 6720
1
There are five total positions that can be played:Point GuardShooting GuardSmall ForwardPower ForwardCenter
There are 5..
5
There are 5..
Since there were many of them, the positions wer probably filled by "extras."
There is five players starting on each team i coach basketball and have for five years and played my whole life there is two gaurds two forwards and a center which are the five main positions.
200
A typical basketball team has at least 5 members because 5 people are needed to be on the court to play the 5 positions.
Their is five starting players.