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Math I know; Basketball I'm a little weaker on.

Assuming that each of the five positions is distinct there are 8! / 3! or 6720 possible combinations.


Assuming that all of the five positions are the same (I know this isn't true; I'm just putting it up for comparison) there are 8 choose 5 ( 8!/(3!*5!)) or 56 possible combinations.


If some of the positions are the same but others aren't, then the answer is somewhere in between.

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โˆ™ 2015-05-02 07:22:38
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Q: How many ways can the 5 starting positions on a basketball team be filled 8 men who can play any of the positions?
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