every out at first base that occurs after a batter has hit the ball is a force out since the batter is required to advance to first base.
batter is out, runners do not advance
When a batter is walked, they can only go to first base at first. Once they are on first base and the next batter is up to bat, they can steal, or advance on a base hit.
As long as the pitcher is the last person to touch the ball before the batter is hit, the ball becomes dead and is counted as a hit by pitch. The runners can only advance if they are forced over by the hit batter.
dead ball, the runner is out and the putout goes to the closest fielder...the batter gets credit for a hit and if there are other runners that are forced to advance by the batter getting first (in this case, a runner on first), he gets to advance also...if there are 2 outs, the batter still gets credit for a hit but the inning is over
no hit, assume runner trying to keep defensive player from throwing to first base.
When a batter is hit by a pitch, the ball is dead.
Ball's dead and runners can't advance.
When a batter is hit with a ball, it is a dead ball. Runners may advance to the next based only if they are forced to do so (e.g. If there are runners on first and third, only the runner on first may advance because they are 'forced' to go to second. The runner on third remains on third).
No. When a batter is hit by a pitch, the ball is dead and no runners may advance. However, if the bases were loaded, then all runners are forced to advance and the runner from third would score.
Neither. It is recorded as a "hit by pitched ball". The batter is not charged with an "At Bat", and is awarded first base, all other runners, if forced, advance one base, if not forced they remain on the base they occupied. The ball is declared "dead" by the umpire and baserunners may not advance unless forced.