Here are two different methods to solve this kind of problem.
1) Use one of the formulae for constant acceleration. In this case, vf2 = vi2 + 2as, where vf is the final velocity, vi is the initial velocity (zero in this case), a is the acceleration (9.8 meters / second2), and s is the distance.
2) Do an energy calculation, as follows: Calculate the potential energy at a height of 6 meters, with the formula PE = mgh. Since we can assume that the entire potential energy gets converted to kinetic energy just before the ball hits the ground, solve for velocity, in the kinetic energy formula.
No. They both hit the ground at the same time. This is because the VERTICAL component of velocity in both cases is the same.
No. They both hit the ground at the same time, because the VERTICAL component of velocity in both cases is the same.
The initial velocity of a dropped ball is zero in the y (up-down) direction. After it is dropped gravity causes an acceleration, which causes the velocity to increase. F = ma, The acceleration due to gravity creates a force on the mass of the ball.
mgh = 1/2 * m * v^2 v = sqrt (2 * 9.8 * 1.2) v = 4.8 m/s [down]
31 m/s
they hit the ground at same instant
5968
it strikes the ground at a velocity of 17.9 ft/s
If it was thrown horizontally or dropped, and hit the ground 3.03 seconds later, then it hit the ground moving at a speed of 29.694 meters (97.42-ft) per second. If it was tossed at any angle not horizontal, and hit the ground 3.03 seconds later, we need to know the direction it was launched, in order to calculate the speed with which it hit the ground.
We will reach terminal velocity just before we hit the ground, then the result of our velocity will be terminal.
You cannot because you do not know how long before the object falls to the ground and so stops moving.
no because the ball is round and it would make no difference in what side you put it on because it has no sides