Bob has 51 cards; Bill has 17.
51
51. Bob has 3/4 of 68.
24
This works out fairly simply, He has 8 football cards and 24 Baseball cards.
13 yellow cards and 16 red cards all together 29 cards
The probability of drawing three diamonds from a standard deck of 52 cards is (13 in 52) times (12 in 51) times (11 in 50), or 1716 in 132600, or about 0.01294.
2
This can be solved algebraically.Set the variable x as the number of cards Bob has.Then express the number of cards that Bill has, in terms of x (Bob's cards).Bob = xBill = only 1/3 as many as BobTheir total is 68.So x + (1/3 x) = 684/3 x = 68Multiply both sides by 3.4x = 204and x =51 and 1/3 x = 17So Bob has 51 cards and Bill has a third as many, or 17, for a total of 68.
The probability of drawing three queens from a deck of cards is (4 in 52) times (3 in 51) times (2 in 50), or 24 in 132,600 or 1 in 5,525.
Exactly four-and-twenty times as much as the worth of one cereal baseball card, one would normally suppose. But, as I have none, I suppose that, if I gathered up all my baseball cards, they would have a combined value of naught. By the bye, how much are your baseball cards worth?
Click your heels together three times and say "Bubbanush!"
They are: 3*7*14 = 231