How many sq ft in tennis court?

Answer 1

From:

http://en.wikipedia.org/wiki/Tennis_court

The court is 78 feet (23.78 m) long, and its width is 27 feet (8.23 m) for singles matches and 36 feet (10.98 m) for doubles matches.[1] Additional clear space around the court is needed in order for players to reach overrun balls for a total of 60 feet (18.3 m) wide and 120 feet (36.7 m) long. A net is stretched across the full width of the court, parallel with the baselines, dividing it into two equal ends. The net is 3 feet 6 inches (1.07 m) high at the posts, and 3 feet (920 mm) high in the center.[2]

Answer 2

Tennis courts are generally 60' X 120' so there would be about 7200 ft^2

Answer 3

A tennis court is 78 ft by 36 ft so the square footage is 2808 Sq. Ft.

Answer 4

A standard tennis court has dimensions of 78 feet x 27 feet.

This results in an area of 2106 sq ft.

So, (2106 / 7800) * 100 = 27 percent

Answer 5

800 sq. ft.