6/8 - 6/8 = 0
By illegitimate, I presume you refer to a no-ball or a wide. Under current rules an over contains 6 balls. Some years back, 8-ball overs were used in Australia if nowhere else. For an over to be complete, 6-balls not including a wide or no-ball must be bowled. If an illegitimate ball is bowled, it must be rebowled. The most illegitimate balls bowled in one over was an over bowled by Curtly Ambrose in his final test on Australian soil which contained 9 no-balls - a total of 15 balls.
6 over 8
There are six balls in an over. There have been 8 ball overs (mainly in Australia before 1970) and 4 ball overs (In England before 1870) All cricket is now 6 ball overs.
6 over 8 = 0.7507 over 8 = 0.875
6/8 * 8/3 = 6/3 = 2.
3/8 + 6/8 = 9/8
6 -w over 8 = -2
If the balls are selected at random, then the probability is 12/95.
3 over 4 minus 3 over 8 can be simplified by finding a common denominator, which in this case is 8. Rewriting 3 over 4 as 6 over 8, the subtraction becomes 6 over 8 minus 3 over 8, which equals 3 over 8.
3 1 7 4 + 8 is 8. Remember to change the denominators into common denominators. (3/4 would turn into 6/8)
2 and 3/4