In a scenario where Drew Brees attempts two passes, we can analyze the outcomes based on the probability of completing each pass. Assuming each pass has a certain probability of being completed (let's denote this probability as ( p )), the possible outcomes are: two complete passes, one complete pass and one incomplete pass (which can occur in two ways), or two incomplete passes. The only outcome where he does not complete at least one pass is if both passes are incomplete. Therefore, the percentage of outcomes resulting in at least one complete pass can be calculated as ( 1 - (1 - p)^2 ), which varies based on the value of ( p ). If, for example, ( p = 0.5 ), then there is a 75% chance of completing at least one pass.
Honestly. I've attempted such a feat. And it is possible due to the weight of the blade. I would advise practice and safety but it IS possible
Possible outcomes with one cube = 6 Possible outcomes with 2 cubes = (6 x 6) = 36 Probability of a double-one (snake eyes) = 1/36 = 2.78% (rounded) Odds: 35 to 1 against
how do we analyze favorable and possible outcomes
There are 25 = 32 possible outcomes.
There are 36 possible outcomes.
The possible outcomes of a coin that is flipped are heads or tails.
There are 23 = 8 possible outcomes.
Counting Principle is used to find the number of possible outcomes. It states that if an event has m possible outcomes and another independent event has n possible outcomes, then there are mn possible outcomes for the two events together.
Possible outcomes of a single dice are 6 ( 1,2,3,4,5,6) So if 5 such dices are rolled then the number of possible outcomes are 6 mulitiplied by 6 five times. 6x6x6x6x6x6=46656 possible outcomes.
Let H mean Head and T mean Tail. The outcomes from flipping a coin twice are the same as flipping two coins together. You might get H + H, or H + T, or T + H, or T + T. So there are four possible outcomes. They are each equally likely but if you ask, "What are the chances of throwing H + H" the answer is 1 out of 4 or 25% or 0.25, and the same for throwing T + T. However, if you ask the question, "What is the chance of throwing a H with a T the probability is 2 out of 4 because there are two ways of doing that. So the probability there is 2 out of 4, or 1 out of 2, or 50% or 0.5
you ether use a graph tree diagram or web diagram to answer the possible outcomes of the question possible outcomes meaning the number of outcomes the person will have in the probability or divide the number of favourable outcomes by the number of possible outcomes favorible outcomes meaning the number of outcomes all together
There are 26 = 64 possible outcomes.