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Upon leaving the aircraft, a skydiver rapidly reaches something called terminal velocity. This is where the resistance of the air matches the mass of the skydiver. At this speed, the skydiver maintains a relatively constant speed. Typically this is around 120mph in a flat body position and takes approximately 10 seconds to reach.
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Wiki User
∙ 13y ago
Wiki User
∙ 12y agoInitially, like any falling object, a skydiver's downward acceleration is 9.8 meters/seconds^2, or about 28-35 feet per second squared. This acceleration reduces over a few seconds and approaches zero as the skydiver reaches terminal velocity. This is because air resistance becomes a larger and larger force as speed increases.
Wiki User
∙ 13y agoI think it would be the acceleration of gravity 9.81 m/s^2...
Anonymous
The acceleration changes of time in this case a few seconds. It goes from 9.8 to 7.2 Btw a 10 year old answered this
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What is a skydivers velocity after 2 seconds?
Acceleration due to gravity is 9.8m/s/s, which is the same as 9.8m/s2. An acceleration of 9.8m/s/s means that with each passing second, the velocity of the skydiver increases by 9.8m/s. Therefore, after two seconds. a skydiver's velocity would be 19.6m/s. The acceleration will continue at 9.8m/s/s until the skydiver reaches terminal velocity, at which point the weight of the skydiver and the air resistance will be balanced, so the net force acting on the skydiver will be zero, at which point there will be no further acceleration.
What is the magnitude of a skydiver's acceleration if it takes 0.75 seconds?
zero
When skydiver slows down from 54 meters to 4 meters by opening his parachute If this takes 0.75 seconds what is the magnitude of the skydiver's acceleration?
the magnitude of the skydivers acceleration is zero as he is decelerating by opening his parachute!
What A skydiver slows down from 54 ms to 4 ms by opening his parachute this change takes 0.75 what is the skydiver acceleration?
If the 0.75 refers to seconds, then his acceleration is -66.66... (repeating) metres per second^2.
A skydiver slows down from 54 ms to 4 ms by opening his parachute. If this takes 0.75 seconds what is the magnitude of the skydiver's acceleration?
66.7 m/s2
Are the forces balanced or unbalanced when a skydiver is accelerating downward?
An acceleration requires an unbalanced force.
Does it mean a skydiver is slowing down if the acceleration of the skydiver decreases as falling progresses?
No.Acceleration is a measure of the rate of change of velocity (speed & direction). If acceleration is decreasing (but still above zero) then this means that the rate at which the speed is increasing in this direction is decreasing.As long as the downward acceleration is greater than zero then the skydiver's speed is still increasing.Once terminal velocity is reached then downward acceleration will equal zero (speed is constant).If the downward acceleration falls below zero (as will happen once his parachute is deployed for instance) then this means he is slowing down.
Skydiver slows down from 65 ms to 5 ms by opening the parachute If this takes 0.75 seconds what is the skydiver's acceleration?
80 m/s 2 up
A skydiver with a mass of 60 kg jumps out of an airplane at a height 5000 m The acceleration due to gravity is 9.8m s2 What is the gravitational potential energy of the skydiver?
2,940,000 Joules
A skydiver of mass 100 kg experiences air resistance while falling How fast is the skydiver being accelerated at?
Less than 9.8 meters (32.2 feet) per second2.That would be his acceleration ... and also the acceleration of the feather falling next to him ... if there wereno air at all.
If a skydiver reaches terminal speed after ten seconds will the skydiver gain more speed during the first second or the ninth second?
I would imagine that it is uniform acceleration up until terminal speed. However, wind resistance will be higher 10000 feet up, so acceleration may be less at the start
What would the force of a skydiver with a mass of 70 kg and accelerates at 9.8 ms2 be?
The force is 686 newtons. (Force = mass x acceleration).
