The period of a wave is the reciprocal of the frequency. ( '1' divided by the frequency)
I believe the equation is as follows
time = 2pi x the square root of (m/k)
where m is your mass and K is your spring constant
2(pi)/B
It is p2 = ka3where p is the orbital period, a is the semi-major axis of the orbit and k is a constant of proportionality.
The equation for the length, L, of a pendulum of time period, T, is gievn byL = g(T2/4?2),where g is the acceleration due to gravity. So, for a pendulum of time period 4.48 sec, the length of the pendulum is 4.99 metres (3 s.f).
Yes, the equation p2 = a3, where p is a planet's orbital period in years and a is the planet's average distance from the Sun in AU. This equation allows us to calculate the mass of a distance object if we can observe another object orbiting it and measure the orbiting object's orbital period and distance.
y(t) = 76*4t, where t = 0,1, 2, ...
An unbalanced equation having diffrent mass on both side of equation is called skeletol equation.
Wavelength = (wave speed) divided by (period)
The period (T) of a circle is represented by the equation: T=1/F, where F is the frequency.
it depends on what b is in the equation. Period = 360 degrees / absolute value of b.
Pi
T=1/f or T=wavelength/ velocity
A. speed=wevelength/weve period
sine wave, with a period of 2pi/w
Formula: Periodxlength The only numbers you plug in are period and length. X remains a variable.
T = 1/f = 2*pi*sqrt(m/k)
You solve this as follows. You call your number "x", and write:x = .323232... (equation 1) Then you multiply this equation by 100 (a one, followed by two zeros - this is because the length of the period is 2), and get: 100x = 32.323232... (equation 2) Now you can subtract equation 1 from equation 2, and solve for "x". This will give you "x" as a fraction.
its very easy the chemical side of a volume is the square root of 444 is equal to the equation of a solution of 20 divided by a atomic group which equals a period
its very easy the chemical side of a volume is the square root of 444 is equal to the equation of a solution of 20 divided by a atomic group which equals a period