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Baseball infields are supposed to be square. Therefore, an infield would be 90x90 for Major League Baseball, maybe 40x40 for third graders, and maybe 60x60 for eighth graders. The numbers refer to the distance between bases.

In any case, the formula for calculating the distance from home plate to 2nd base is A Squared + B Squared = C Squared, where A is the distance from home plate to 1st base, B is the distance from 1st base to 2nd base, and C is the distance from home plate to 2nd base.

This sounds like your league has an infield of 50x50. Using the formula above, the distance from home plate to 2nd base would be 70.71 feet, which comes out to 70 feet and 8.5 inches. Your league probably just defines it as 70 feet for simplicity in measuring, thus resulting in the term 50x70.

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Q: What is the distance from home plate to second base on a 50x70 baseball field?

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about 127 ft from the tip of home to the back of 2nd base

The baseball playing field (or diamond) is shaped like a diamond. There are three bases (first, second, and third) are on the corners away from home plate. The distance between these bases (on the basepath or distance straight from first base to second base, or second base to third base, etc.) is 90 feet in Major League baseball. In Little League, the distance in 60 feet.

It would be measured in feet.

The distance from home plate to second base on a regulation Major League Baseball field is 121 feet, zero inches. Another answer: Major League Baseball rule 1.04 defines the distance from home plate to 2nd base as 127 feet, 3 3/8 in.

From home to first, first to second, etc.. the distance between bases is 90 feet. All the way around is 360 feet. But if you're asking what the distance is around a whole baseball field, each field is different. Some have much bigger fields than others. The only thing that is the same is the infield.

99 feet. You can find the distance between home and second on any baseball or softball field by using the following formula: A squared plus B squared equals C squared. A is the distance between home and first base B is the distance between first base and second base C is the distance between home and second base.

90 feet, the same between all bases in baseball. If you mean going around the bases, the shortest distance would be 270 feet, first to second, second to third and third to home.

Bases are different distances apart at different levels of play in baseball. Here is how you can find the distance across the diamond (home to second, or first to third) on any field: What is the distance between bases? Square that answer (multiply it by itself). Double that answer. Find the square root of that answer. The answer you get will be the distance from home to second or from first to third.

the distance between the bases are 60 feet in little league, and youth baseball

Bases are different distances apart at different levels of play in baseball. Here is how you can find the distance across the diamond (home to second, or first to third) on any field: What is the distance between bases? Square that answer (multiply it by itself). Double that answer. Find the square root of that answer. The answer you get will be the distance from home to second or from first to third.

I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.

It is the distance added together around it.

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