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When the air resistance acting upwards on a skydiver equals half his weight, the resultant force on the skydiver will therefore be only half as much as his weight. Since acceleration is proportional to resultant force, the acceleration will only be half as much if the only force acting was gravity. Acceleration due to gravity is 9.8 metres per second squared, so the answer is 4.9 metres per second squared.

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Q: What is the acceleration of a skydiver when air resistance builds up to half his weight?

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The acceleration will be 0.7 of the initial acceleration. 0.7x9.81=6.87m/s^2

5 m/s^2 (or 4.9 m/s^2 if you want to be exact) Since acceleration is zero when air resistance is equal to weight of object, and the most acceleration possible is 10 m/s^2 (or specifically, 9.8 m/s^2), then when air resistance is half of her weight, acceleration is also half, meaning 5m/s^2.

Acceleration due to gravity is 9.8m/s/s, which is the same as 9.8m/s2. An acceleration of 9.8m/s/s means that with each passing second, the velocity of the skydiver increases by 9.8m/s. Therefore, after two seconds. a skydiver's velocity would be 19.6m/s. The acceleration will continue at 9.8m/s/s until the skydiver reaches terminal velocity, at which point the weight of the skydiver and the air resistance will be balanced, so the net force acting on the skydiver will be zero, at which point there will be no further acceleration.

Once a skydiver jumps off the plane, they will begin picking up speed. However, as the speed of the skydiver increases, the amount of air resistance acting upon them will also increase. The skydiver will continue to accelerate while his or her weight is greater than the air resistance. When the force of the air resistance becomes equal to the weight of the skydiver, the skydiver will stop accelerating and will continue falling at a constant speed, this is known as the terminal velocity. While travelling at terminal velocity, the skydiver will be able to adjust his or her body position in a way that will increase or decrease the air resistance and allow the diver to alter their speed. Releasing his or her parachute will drastically increase the amount of air resistance and therefore slow their descent significantly.

No, because acceleration of free fall is gravitational acceleration minus air resistance. Weight does not involve air resistance.

Terminal airspeed for a skydiver is approximately 120mph (oriented on belly). Mass of the skydiver affects the speed ! So heavier generally falls faster. (drop a ping pong ball versus a golfball) So, the weight of the skydiver will not affect the air resistance. His clothing will affect it, and his body position. Lastly, air pressure changes with altitude, so the density of the air is less as you go higher. So, exit altitude will also be a factor, as the air pressure will change the air resistance due to density. Bet you're sorry you asked. As a skydiving instructor, if I weighed 1/10 my weight, i would expect to fall really slow. something ridiculous, like 30mph. If you made air resistance 1/10th we would get going quite fast. 200-250mph? Col Joe Kittenger jumped form 103,000feet from a balloon. He experienced an almost frictionless descent for a bit, which led people to believe to break the sound barrier.

500 N is pressumably the weight, due to gravity. "Terminal velocity" means that the forces are in balance; the total force acting on the skydiver are zero. This is only possible if there is a 500 N force due to friction, to counteract the weight.

The downward force exerted on objects due to gravity.

The weight exceeds the force of air resistance, but as the speed increases the air resistance increases, so the net force (weight - air resistance) falls. When the difference becomes zero the acceleration ceases and you have terminal velocity.

The forces involved in the freefall part of a skydive are Gravity and air resistance (drag). As the parachute is deployed, drag opens the canopy and the skydiver's weight provides tension on the lines. When the canopy has opened, the skydiver's weight is supported lift provided by the canopy. The canopy also generates thrust and drag, like an aeroplane's wing.

No. Things are only weightless in the absence of a gravitational field or in constant acceleration (Inertial weight or mass) (Ask any skydiver.)

The terminal velocity of an object moving through a fluid under the force of gravity (let's assume the fluid is air for sake of discussion) occurs at the speed where the drag force of the air on the object becomes equal to the weight of the object. At this point the object has stopped accelerating and is in uniform motion (constant speed).For example, a skydiver jumping out of a plane will accelerate towards the Earth. At first the skydiver is accelerating at 9.8 m/s2, the gravitational acceleration of the Earth. But as he accelerates to higher speed, drag force becomes greater and the rate of acceleration slows. Drag force is proportional to the square of the speed, by the way. Eventually the skydiver will reach a speed (around 120 mph depending on the orientation of the skydiver's body) where the drag force is equal to his weight. That will be his terminal velocity.

The world has mass but no weight. Mass is a measure of quantity of matter, Weight is indicated by the pull on a mass in a gravitational field, or equivalently resistance to acceleration.

If air resistance is 1/4 of the falling object's weight, then the net force on it ...(gravity + air resistance) ... is 3/4 of its weight downward. Its acceleration thenmust be 3/4 of the acceleration of gravity, or 7.36 meters (24.1 feet) per second2.The mass of the object, or how many of them there are, makes no difference.You took care of that when you said that the air resistance is 1/4 of its weight.

The weight of the sky diver has minimal effect on freefall time. Body position and amount of surface area exposed for wind resistance to affect are the two largest factors, and are interrelated to one another.

The maximum weight for a person to skydive is 220 pounds.

Yes. Neglecting the effects of air resistance, all objects near the surface of the earth fall with the same constant acceleration, regardless of their mass/weight.

This is known as terminal velocity.

Being a layman, this will be a lay answer until an expert, or skydiver improves it. As I recall, the acceleration of gravity is 32 feet per second per second. My calculations suggest that in a vacuum, the skydiver's velocity would be 288 feet per second, or 196 miles per hour. However, since the diver is falling through the air of the atmosphere, there is frictional resistance, resulting in what is called drag, which limits the falling speed. Depending on the weight of the diver, the size and amount of loose clothing the diver wears, there will be a limited maximum speed of fall, refered to as terminal velocity, generally in the range of 120 to 125 miles per hour.

as much as en elf

No. The Acceleration due to gravity is the same for all objects. (-9.81m/s squared) (Assuming that there is no air resistance)

Varies depending on body position and weight of the skydiver. Could be anywhere from 100 to over 200 miles per hour.

Exactly the same as hits a passenger sitting comfortably in another airplane at the same altitude:A downward force called his "weight", and a downward acceleration of 9.8 meters per second2.

adding weight and by decresing air recistance

A falling rock in vacuum accelerates at 9.8 meters per second2 ... the acceleration of gravity at the earth's surface.A falling rock in air has a smaller acceleration than in vacuum, because of air resistance;the exact figure depends on the rock's weight and shape.A falling rock in water has an even smaller acceleration than it air, because of water resistance; the exact figure again depends on the rock's weight and shape.