It's not really a question of better, more of different. What decides how fast the top speed of the bike is, and how nippy it is off the start is the ratio between the tooth count of the crankset, and the tooth count of the freewheel. With a smaller freewheel you can have a smaller crankset, a slightly lighter bike and get the same feel of the bike as with a bigger crankset and a bigger freewheel.
No. a 9T sprocket will only fit a cassette hub, and not freewheel hubs.
I'm assuming you're talking about a BMX here, which use the words a bit different from the rest of the cycling world.So it's the size/tooth count of the freewheel that you're asking about.And then it's just as much about what you want as what you need.When you change the sprocket/freewheel size you change the gear ratio.A big sprocket and a small freewheel lets you go fast, but you'll have to push harder.A bigger freewheel will cost you some top speed, but will make it easier to get the bike moving.A very common combo is 25t front and a 9t rear.
9t=702 t=702/9 t=78
9t + 9 = 9 (t + 1)
9t = 4t + 120 9t-4t = 4t - 4t + 120 5t = 120 5t/5 = 120/5 t = 24 24 is your answer
f(x) = 4.1cos9t the derivitative of just cos(9t) is -9sin9t then just multiply -9 by 4.1 (-36.9) the derivative is -36.9sin(9t)
3
-9w + zt + wz - 9t = (z - 9)(t + w)
9t + 15t= 216 24t=216 t=216/24 t=9
They are the same.
9t + 5 = 7 - 2t Subtract five from both sides: 9t = 2 - 2t Add 2t to both sides: 11t = 2 Divide both sides by 2 t = 2/11 or about .1818
The GCF is 3t.