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How many gallons of water would an 20' round by 48 deep swimming pool hold?
Wiki User
∙ 14y ago
If the 20' is the diameter of the pool (radius 10 feet) and the depth is 48 inches (4 feet) the volume of the pool in cubic feet would be found by the formula pi x r2 x h - with pi as 3.14159, r2 as 100 and h as 4
... which gives 1256.636 cubic feet
1 cubic foot of water = 7.4805195 US gallons (or 6.2288355 Imperial gallons), so 1256.636 cubic feet would be 9,400.2901 US gallons (or 7,827.3789 Imperial gallons)
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If, however, the 20' is the circumference, then the radius would be just over 3.18 feet and the formula becomes 3.14159 x 10.13 x 4
... which gives 127.297 cubic feet
That converts to 952.25 US gallons or 792.9 Imperial
Wiki User
∙ 14y ago
Wiki User
∙ 13y agoIf the pool is 8 feet at the deep end and 3 feet at the shallow end, the total volume will be 39,494 gallons of water.
Wiki User
∙ 12y agoCant work it out without the depth and do you really mean 20 inch by 40 inch? that's tiny.
Anonymous
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