~1
1 mole of sucrose cotains 12 multiply by 6.023 exponent 23 atoms.
1 M = 1 mole/liter. so 2 M sucrose would contain 2 moles of sucrose in 1 liter of solution.So to find the volume of solution with 1 mole sucrose:V = (1 mole) / ( 2 mole/liter) = 0.5 liter ; 0.5 liter * (1000 mL/liter) = 500 mL
3.65 moles sucrose (11 mole O/1 mole C12H22O11)(6.022 X 1023/1 mole O) = 2.42 X 1025 atoms of oxygen ====================
15 grams sugar per liter is the concentration, in terms of mass per volume. To express the concentration in molarity (assuming the sugar is sucrose): 15 g sucrose * (1 mole sucrose / 342 g sucrose) / 1 L = 0.0439 M aqueous sucrose
FAT
~1
About 36 ATP for aerobic cellular respiration.
1 ATP is equal to 59 KJ
1 ATP is used to begin.Also another ATP is used in glycolisis.
3 ATP
The most ATP are produced during the last stage of cellular respiration-- the electron transport chain which involves chemiosmosisThe theoretical yield for eukaryotes is 36 ATP per glucose moleculeOne ATP generated for each proton pump activatedMultiplied by 2=2 two pyruvates from glucose= 10 NADH = 2 glycolysis + 2 oxidation of pyruvate (2) + 6 from Krebs2 FADH22 ATP from glycolysis + 2 ATP from Krebs10 x3=30 ATP from NADH + 2x2=4 ATP from FADH2 + 4 ATP= 38 ATP producedAccurate for bacteria not eukaryotes= NADH in cytoplasm from glycolysis need 1 ATP/NADH molecule36 potential yield
64 net...68 are produced overall but 2 ATP's are used in the reaction per molecule of glucose.
4 ATP molocules are made from 1 NADH and 1 FADH2 MO
Net 3 ATP or in other words, up to 3 ATP or less.
1
1 mole of sucrose cotains 12 multiply by 6.023 exponent 23 atoms.