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The simplest method is to reverse the digits of the original number and check to see if the reversed number is equal to the original. This is not an efficient way of doing it but, for ints or long ints, it works well enough.

void main()

{

// get the number to check

long int n;

printf("ENTER A NUMBER: ");

scanf("%ld",&n);

long int n1,mod;

// make a copy of the original number in n1

n1=n;

// store the reversal in rev

long int rev=0;

while(n>0)

{

// grab the rightmost digit of n

mod = n%10;

// shift all digits of rev left, then add in the new digit

rev = rev * 10 + mod;

// shift all digits of n to the right (removing the rightmost one)

n = n / 10;

}

// after the loop, rev will have the opposite digit ordering of n1;

// if these two values are equal, then we have a palindrome

if (n1 == rev)

printf("%ld is a palindrome\n",n1);

else

printf("%ld is not a palindrome\n",n1);

}

Alternate method:

Split the number into its digits, as on the example below: Number: 3592 1st digit: 3592%10 = 2 3592/10=359. ... 2nd digit: 359%10 = 9 etc. Store these into an integer array, then check if all digits correspond to digits at the reflected position.

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Q: How do you write a program in C to check whether a number is a palindrome or not?
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