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Q: Ball kicked into the air at an angle of 34.0 degrees above the horizontal the initial velocity of the ball is 25.0 ms How long is the soccer ball in the air?

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Initial velocity is 10 m/s in the direction it was kicked. Final velocity is 0, when friction and air resistance finally causes it to come to a halt.

You kicked the rock with an initial velocity of 3.4 m/s.

If it is kicked at 30 degrees to the horizontal then it will travel 27.7 metres.

initial velocity of the kick = 28.06 m/s

When a ball is kicked at an angle, there is no acceleration along the horizontal direction (since there isn't any force along the direction ,ignoring viscous forces), so , its velocity along the horizontal direction remains unchanged.... according to the 1st law , velocity changes only when a net resultant force is applied on the ball , so , Newton's law is valid. only the initial angle of kick and the vertical component of velocity are mainly responsible for the distance travelled by the ball horizontally....

At the top of it path or anywhere else the Earth's gravity accelerates the ball downward. Regardless what the horizontal mothion is (disregarding air resistance), there are no accelerations after the kick. A ball kicked straight up to the same height will hit the ground at the same time as a ball kicked at 45 degrees.

Velocity = Distance/Time = 28/1.4 = 20 m/s

The record speed for a soccer ball to have been kicked by a pro soccer player is 110 mph.

When it's at its maximum height its speed will be zero.

I assume the question is referring to a ball say that is being kicked, in this case some fairly simplistic physics determines that 45 degrees is the perfect angle, this calculation relies upon the fact that the ground is at the same height when it was kicked as when to when it comes to rest. (Delta Yx =0. Hence a level ground) However... If you are talking about a shot put for instance there is a different story, the optimum angle for this type of throw would be around 42 degrees. This value is different from the first due to the differential in heights between Y(x0) and Y(xfinal) where X is distance, Y states the vertical plane and 0 when t=0 (initial height) and then final when Vx&Vy=0 (aka rest). A key point to remember in the proof of this is that velocity, time and distance are all independent of mass. Regardless of how you choose to calculate the initial velocity the explanation stated above is always true for the angle both in a vacuum and in a real world environment. You didn't ask for a scientific proof so in summary: 45 degrees for a ground object (eg. football/soccer) 42 degrees for an object thrown from torso height (eg. shotput) - Approximation

It never happened. Einstein left his Munich school in order to study in Zurich, where he flunked his initial entrance exams.

In soccer, the soccer ball has projectile motion when it is kicked, head-butted, when the speed changes, and when the velocity changes.

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