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A golfer tees off and hits a golf ball at a speed of 31 ms and at an angle of 35 degrees what is the horizontal velocity component of the ball?
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∙ 13y ago
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∙ 13y ago
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A golfer tees off and hits a golf ball at a speed of 31 ms and at an angle of 35 degrees What is the vertical velocity component of the ball?
17.8 m/s
A golfer tees off and hits a golf ball at a speed of 31 ms and at an angle of 35 degrees. What is the vertical velocity component of the ball Round the answer to the nearest tenth of a ms.?
the vertical component of the balls initial velocity is Ay= 48 sin 45 34m/s
A golfer strikes a golf ball at an angle 17 degree above the horizontal. with what velocity must the ball be struck in order to reach the green which is a horizontal distance of 250m from the golfer?
To solve this problem you use the derived formula ∆dh=(V1h2(sin2Ѳ))/g 250m=V1h2(sin2(17))/9.8m/s2 V1h=((sin(17))/9.8m/s2)1/2 V1h= 64.7292201m/s V1h= 65m/s
A golfer strikes a golf ball at an angle 17 degree above the horizontal. with what velocity must the ball be struck in order to reach the green which is a horizontal distance of 250m from the golfer.?
To solve this problem you use the derived formula ∆dh=(V1h2(sin2Ѳ))/g 250m=V1h2(sin2(17))/9.8m/s2 V1h=((sin(17))/9.8m/s2)1/2 V1h= 64.7292201m/s V1h= 65m/s
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A golfer tees off and hits a golf ball at a speed of 31 ms and at an angle of 35 degrees How long was the ball in the air?
a
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A golfer tees off and hits a golf ball at a speed of 31 ms and at an angle of 35 degrees What is the maximum height attained by the ball?
25.3
A golfer tees off and hits a golf ball at a speed of 31 ms and at an angle of 35 degrees. What is the maximum height attained by the ball?
25.3
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